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Find a geometric way to prove the inequality! (Posted on 2007-11-07) Difficulty: 3 of 5
If 0 < a < b < c < d then prove that

a/b + b/c + c/d + d/a > b/a + c/b + d/c + a/d.

See The Solution Submitted by Chesca Ciprian    
Rating: 3.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Similary...but different! | Comment 2 of 5 |
(In reply to No Subject by Mike C)

Hi!

I'm agree when you say that (d-b)/a+(b-d)/c>0 but

when you say similary (alike) ..........

(c-a)/d + (a-c)/b > 0 i'm not agree!

because d>b.

(Bad) example :

1<2<3<4

(3-1)/4+(1-3)/2 = 2/4-2/2 = -1/2 < 0

Edited on November 7, 2007, 4:55 pm
  Posted by Chesca Ciprian on 2007-11-07 14:41:56

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