For a triangle ABC, Area/R=4. Find
acosA+bcosB+ccosC.
Note:R is circumradius of triangle ABC.
(In reply to
re: Solution by Praneeth)
If we define
Area(AOB) = (R^2/2)*sin(AOB)
Area(BOC) = (R^2/2)*sin(BOC)
Area(COA) = (R^2/2)*sin(COA)
with AOB, BOC, and COA as directed angles with at least two less than 180 degrees, then this should take care of an obtuse angled triangles.
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Posted by Bractals
on 2008-01-22 15:10:46 |