H(y) is a continuous function such that:
y
∫ H(n) dn = H(y)
0
Determine H(10)+ H(20)
from the fundamental theorem of calculus we have that
H'(y)=H(y) now this is that famous differential equation with solution
H(y)=c*e^y
now puting this into the integral equation we get
c*(e^y - 1)=c*e^y
now the only solution is c=0 thus
H(y)=0
and H(10)+H(20)=0
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Posted by Daniel
on 2008-01-28 12:13:55 |