Eight points are placed on the surface of a sphere with a radius of 1. The shortest distance between any two points is greater than 1.2. How can the points be arranged?

Hint: They are not arranged as a cube. The cube would have an edge length of only 2/sqrt(3) = 1.1547.

(In reply to Solution by Dej Mar)

A regular octahedra has only six vertices.

Posted by Bractals on 2008-02-01 13:34:43