The cubic equation y³ + by + b = 0 has three roots y₁, y₂ and y₃ with y₁ ≥ y₂ ≥ y₃, where b is real and non zero, such that:

y₁²/ y₂ + y₂²/ y₃ + y₃²/ y₁= -8

Determine y₁, y₂ and y₃

From Praneeth:  "So, 8/b=-1 => b=-1"

Should of course be 8/b=-1 => b=-8, giving y1=y2=y3=-2.

 

 

Posted by xdog on 2008-02-02 20:04:30