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Curious Real Additive Relationship (Posted on 2008-04-12) Difficulty: 2 of 5
Are there any non zero real triplet(s) (p, q, r) that satisfy the following system of equations?

p + 1/p = q, q + 1/q = r, and r + 1/r = p

If such triplet(s) exist, find at least one of these. Otherwise, prove that no such triplet can conform to the given conditions.

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (2 votes)

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Solution Accept no substitutes | Comment 2 of 5 |
Agree completely with Charlie, but there is no need to do all those substitutions.

If p > 0, then so is q and r
But, p < q < r < p, which is impossible.

If p < 0, then so is q and r
But, p > q > r > p, which is impossible

And p cannot be 0

So, the equations have no real solution



  Posted by Steve Herman on 2008-04-12 20:25:36
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