C^2-3CD=C-D --> 9C^2 - 27CD = 9C - 9D -->
9C^2 - 9C = 27CD - 9D --> (3C-2)(3C-1)-2 = 9D(3C-1) -->
9D = 3C-2 - 2/(3C-1)
Since D is an integer, 9D is also --> C=0 or 1 only -->
(0,0) and (1,0) only.
blackjack
flooble's webmaster puzzle