There is only the trivial solution C=1, D=0.
Since C divides C-D, it follows that D is non-positive.
Similarly, C-3D divides C-D, so C-3D <= C - D, so that D is non-negative.
Since C^2 divides C, C must be 1.
Edited on April 15, 2008, 8:28 pm
blackjack
<a href="http://c.casalemedia.com/c?s=51816&f=3&id=0" target="_blank"><img src="http://as.casalemedia.com/s?s=51816&u=http://perplexus.info&f=3&id=0&if=0" width="120" height="600" border="0"></a>
flooble's webmaster puzzle
Not much to this one
