All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Just Math
>
Calculus
Rooting For The Limit (
Posted on 2008-04-23
)
Evaluate:
Limit ((2
y
+ 2
2y
+ 2
3y
)/3)
1/y
y → 0
Bonus Question
:
Work out the following limit:
Limit ((2
y
+ 6
y
+ 18
y
)/3)
1/y
y → 0
See The Solution
Submitted by
K Sengupta
Rating:
3.5000
(2 votes)
Comments: (
Back to comment list
| You must be logged in to post comments.
)
Solution
| Comment 2 of 6 |
The limit to both equations is one.
As y→0, the value inside the parentheses approaches 1 while the exponent approaches infinity. One to any power equals 1.
Posted by
hoodat
on 2008-04-23 14:45:34
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2025 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information