....................I 've erroneously solved the case that A^2 DIVIDES B
and proved the oppposite- then edited by adding this remark...........................................................
Text prior to my edit:
LET B/2A^2=K
A^2+B=A^2*(2K+1) =(SAY ) N
FOR N TO BE A SQUARE OF INTEGER (2K+1) MUST BE A SQUARE OF INTEGER,WHICH IS POSSIBLE , for if
b=32 and A=2 k=4 k*2+1=9
and 32+4 is a square
..................Now i am going to solve the original -hopefully
Edited on May 7, 2008, 11:31 am