What is the center of gravity of the perimeter of a triangle (as when a piece of wire is bent into triangular form)?

The center of gravity a solid, homogenous triangle would be the centroid of the triangle.

'The centroid of a triangle is the point of intersection of its medians (the lines joining each vertex with the midpoint of the opposite side).'

If the three vertices are located at
(x₁,y₁), (x₂,y₂), and (x₃,y₃),
then the centroid is at
(1/3*(x₁ + x₂ + x₃ , 1/3*(y₁ + y₂ + y₃)).
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See later post for the center of gravity of the triangle where the triangle is not a solid, but where the mass is located only at the perimeter.

 

Edited on May 20, 2008, 10:28 am

Posted by Dej Mar on 2008-05-19 06:08:00