All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Near Cyclic Conundrum (Posted on 2008-05-19) Difficulty: 3 of 5
Determine all possible triple(s) (p, q, r) of rational numbers that satisfy the following system of simultaneous equations:

p2(q+r) = 5, q2(r + p) = 8, and r2(p + q) = 9

See The Solution Submitted by K Sengupta    
Rating: 3.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution | Comment 3 of 4 |
(In reply to re: Solution by Steve Herman)

Should have mentioned it as the only rational solution.
I modified the statement and sorry for the confusion abt
that statement.

  Posted by Praneeth on 2008-05-20 02:41:40
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information