I found it convenient to use y = 1/u^2. Then
f(y) = sqr ( 1/u^2 + sqr (1/u^2 + 1/u) ) - 1/u
= 1/u [ sqr (1 + sqr (u^2 + u^3) ) - 1 ] as u goes to 0 we can expand
sqr (1 + sqr( u^2 + u^3 ) ) -> 1 + sqr(u^2 + u^3)/2 -> 1 + u/2. So
f(y) -> 1/2
Edited on May 24, 2008, 1:33 pm
blackjack
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flooble's webmaster puzzle
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