In the problem Calendar cubes you figured out the maximum amount of days you could fit on two cubes by putting numbers on both cubes and using the faces of the cubes to combine and make more numbers.
In Calendar cubes pt 2 You figured out how many months you could fit on two cubes.
Now in calendar cubes pt 3 you must figure out how many days of the year you can fit on two cubes. E.G one cube says mar(for march) and another says 5. so you could make the date march 5 and that would count as one date.

To represent months you may use
a) the first letter of that month
b) the first and second letter of that month
c) the first three letters of that months. So for january you could use either j, ja or jan to represent that month.
Also no two letters or letter combinations can represent the same month. So j cannot stand for june and july, but you can have j stand for june and ju stand for july. Also note that one month symbol (lets say au for august) can be on 1 face of 1 cube.

you could get all 12 months onto one die. Assuming for sake of description simplicity that both cubes are of equal size, write the three letter abbreviation of a month near the top of a cube face. Then, looking at teh face with writing on in, rotate the cube 180 degrees, keeping the written face viewable, and write the next three letter abbreviation on the top of the same face (the first month is showing upside down on the bottom half of the face), giving you two months on the first face. This method can be repeated on six faces giving you all 12 months on one die. A similar procedure could be used to get 12 day numbers as well (though I'm not sure this can't be beaten).
Finally, you need to construct a little groove that the dice can fit in which will obscure bothe of their bottom halves. This gives me 144 days of the year on two dice.

Posted by Cory Taylor on 2003-04-14 04:22:30