Find the minimum area of a triangle whose sides and altitudes are six different integers.

(In reply to Computer Solution by Bractals)

Am I missing something?

By definition of a triangle's altitude, h_a would be perpendicular to side a.  This would mean, in accordance to Pythagoras, that
a₁ = SQRT((75)² - (60))²) and a₂ = SQRT((100))² - (60))²), where a = a₁ + a₂.  Thus a₁ and a₂ equals 45 and 80, respectively, which means side a should equal 125, not 35. 

Posted by Dej Mar on 2008-07-30 15:04:45