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Students in a tournament (Posted on 2008-09-05) Difficulty: 2 of 5
Ninth- and tenth-grade students participated in a tournament. Each contestant played each other contestant once. There were ten times as many tenth-grade students, but they were able to win only four-and-a-half times as many points as ninth graders.

How many ninth-grade students participated, and how many points did they collect?

Note: one point for every win.

See The Solution Submitted by pcbouhid    
Rating: 2.3333 (3 votes)

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Obvious solution | Comment 5 of 7 |

This is another problem not clearly defined.  We are not told what games/sports are involved, but only that all compete as pairs (two participants in each game).  Since not told otherwise, I shall assume there can be no draws/ties.  This is not defined as a contest of one grade vs another, so I shall assume that each contestant played every other contestant of either grade.

The answer is patently obvious: there was one ninth-grader, and ten tenth-graders (ten times as many tenth-graders).

The ninth-grader beat each of the tenth graders, hence scoring 10 points.  Clear each tenth-grader lost to that ninth-grader so got no points for those matches.  When the tenth-graders played each other, there were 45 games (10*9/2), so the tenth-graders collectively scored 45 points.  Their 45 points are 4.5 times the points scored by the ninth-grader (10).

I'll post, and then look at other comments. What is supposed to be the point of the problem?


  Posted by ed bottemiller on 2008-09-05 15:25:57
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