The sum of n+1 consecutive squares, beginning with the square of
n(2n+1), is equal to the sum of the squares of the next n consecutive integers.

   n=1      32 + 42 = 52
   n=2      102 + 112 + 122 = 132 + 142
      .
      .
      .

Prove that the proposition holds for all integers greater than zero.

(In reply to solution (spoiler) by Daniel)

sorry, seems my summation symbols are not showing properly, so if you are seeing the wierd accented O like I am, substitute a summation symbol for it.

Posted by Daniel on 2008-09-26 12:39:31