Ten primes, each less than 3000, form an arithmetic progression. Find them.
Interesting that the numbers are 210 apart. 210 = 2 x 3 x 5 x 7.
As a guess, would twelve consecutive primes have to be at least 2310 apart? 2310 = 2 x 3 x 5 x 7 x 11
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Posted by Leming
on 2008-09-30 14:59:32 |