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Primes in arithmetic progression (Posted on 2008-09-30) Difficulty: 3 of 5
Ten primes, each less than 3000, form an arithmetic progression. Find them.

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Question Interesting | Comment 4 of 9 |

Interesting that the numbers are 210 apart.  210 = 2 x 3 x 5 x 7. 

As a guess, would twelve consecutive primes have to be at least 2310 apart?  2310 = 2 x 3 x 5 x 7 x 11


  Posted by Leming on 2008-09-30 14:59:32
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