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Primes in arithmetic progression (Posted on 2008-09-30) Difficulty: 3 of 5
Ten primes, each less than 3000, form an arithmetic progression. Find them.

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Slightly larger | Comment 8 of 9 |

Staying within the bounds of 100000 (i.e. 9592 primes), and making use of the aperçu from a prior post that the addend must be a multiple of 210 (nice reasoning!), I found only three higher sets which allowed progressions of 10 primes -- but did not find any sets with more:

30427 + 4830 (1..9)

34913 + 2100 (1..9)

52879 + 420 (1..9)

so it appears that the logic of division- of the addend by 2,3,5,7 does not seem to have an obvious extension (e.g. by use of 11, etc.).

 


  Posted by ed bottemiller on 2008-09-30 20:07:00
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