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Trisected Triangle (Posted on 2006-02-03)

A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.

No Solution Yet Submitted by Chris, PhD

Rating: 4.5000 (4 votes)

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Answer

| Comment 12 of 14 |

The required value of k is 5/9.

Posted by K Sengupta on 2008-11-17 01:42:15

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