Prove that if a triangle's area and sides are all integers, its perimeter must be even.
(In reply to
complete solution by Daniel)
My solution is similar.
Squaring Heron's formula and substituting s=p/2, we see area squared equals (p/2)(p/2-a)(p/2-b)(p/2-c) or (p/2)(p-2a)/2*(p-2b)/2*(p-2c)/2 or p(p-2a)(p-2b)(p-2c)/16.
Given area is an integer, assuming p is odd leads to a contradition as then p(p-2a)(p-2b)(p-2c) is odd, and area squared wouldn't be an integer. So the perimeter must be even.
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Posted by Gamer
on 2009-01-16 23:35:09 |