I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.
Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:
| | C/D | F/B/G/E/C | G/E/C |
| X | | F/G/C/D | F/G/E/C/D |
| F/E/C/D | F/G/C/D | F/G/E/C/D | F/E/C/D |
(In reply to
re(3): problems with computer program by Charlie)
The swapped elements are A-E and B-D.
This turns:
0 (ABCDEF) into CF
1 (BC) into BD
2 (ABGDEG) into G
3 (ABCDG) into CEG
4 (BCFG) into CDFG
5 (ACDFG) into BCEFG
6 (CDEFG) into ABCFG or (ACDEFG) into BCFG
7 (ABCF) into CDEF
8 (ABCDEFG) into CFG
9 (ABCFG) into CDEFG
re(4): problems with computer program
