All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Logic
My Wonky CalcuLESS (Posted on 2009-02-18) Difficulty: 3 of 5
I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.

A
F B
G
E C
D


Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:

C/DF/B/G/E/CG/E/C
XF/G/C/DF/G/E/C/D
F/E/C/DF/G/C/DF/G/E/C/DF/E/C/D


See The Solution Submitted by rod hines    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(5): problems with computer program | Comment 8 of 13 |
(In reply to re(4): problems with computer program by Robby Goetschalckx)

ok; I never tried ABCF for 7 (only ABC); the only other alternative needed (which I had tried) was the ABCFG for 9 rather than ABCDFG.

Using those two alternatives, the program does find the solution you found.


  Posted by Charlie on 2009-02-19 11:48:19
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information