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My Wonky CalcuLESS (Posted on 2009-02-18) Difficulty: 3 of 5
I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.


Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:


See The Solution Submitted by rod hines    
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re(4): problems with computer program | Comment 7 of 13 |
(In reply to re(3): problems with computer program by Charlie)

The swapped elements are A-E and B-D.
This turns:
0 (ABCDEF) into CF
1 (BC) into  BD
2 (ABGDEG) into G
3 (ABCDG) into CEG
4 (BCFG) into CDFG
5 (ACDFG) into BCEFG
6 (CDEFG) into ABCFG or (ACDEFG) into BCFG
7 (ABCF) into CDEF
8 (ABCDEFG) into CFG
9 (ABCFG) into CDEFG

  Posted by Robby Goetschalckx on 2009-02-19 05:15:43

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