I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.

Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:

| C/D | F/B/G/E/C | G/E/C |

X | | F/G/C/D | F/G/E/C/D |

F/E/C/D | F/G/C/D | F/G/E/C/D | F/E/C/D |

(In reply to

re(3): problems with computer program by Charlie)

The swapped elements are A-E and B-D.

This turns:

0 (ABCDEF) into CF

1 (BC) into BD

2 (ABGDEG) into G

3 (ABCDG) into CEG

4 (BCFG) into CDFG

5 (ACDFG) into BCEFG

6 (CDEFG) into ABCFG or (ACDEFG) into BCFG

7 (ABCF) into CDEF

8 (ABCDEFG) into CFG

9 (ABCFG) into CDEFG