All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
A digital arrangement (Posted on 2005-06-30) Difficulty: 3 of 5
Without using any arithmetical symbols (+, -, *, /, or similar; other math symbols; decimal comma or periods; letters; even parentheses) or, in short, anything but the digits, build a number with the digits 1, 3, 5, 7 and 9, that is equal to a number built with the digits 2, 4, 6 and 8 (each digit used once and only once).

Note: This is not a trick. It was extracted from a book edited by Angela Dunn, a mathematician who gathered problems that appeared in many scientific periodical revues!

See The Solution Submitted by pcbouhid    
Rating: 3.2857 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts A slight modification | Comment 19 of 21 |
What if none of the digits are "used up" naming the base?

Define <2468> to be the set of 4 digit numbers consisting of the 4! permutations of 2468.

Maybe one or more numbers in <2468> in some base n where n>8 is equal to a number in <13579> in some other base m where m>9.

  Posted by Larry on 2009-05-17 22:40:54
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information