perplexus.info :: Just Math : x + y * <sup>3</sup>√2 + z * <sup>3</sup>√4 = 0

x + y * ³√2 + z * ³√4 = 0 (Posted on 2009-10-15)

Each of x, y and z is a rational number such that: x + y * ³√2 + z * ³√4 = 0.

Prove that x=y=z=0 is the only possible solution to the above equation.

See The Solution Submitted by K Sengupta

Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: Non-rigorous argument

| Comment 2 of 14 |

(In reply to Non-rigorous argument by Jim Keneipp)

I disagree with #3.

2-sqrt(2) + sqrt(2) = 2

Posted by Jer on 2009-10-15 14:59:19

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