perplexus.info :: Just Math : x + y * <sup>3</sup>√2 + z * <sup>3</sup>√4 = 0

x + y * ³√2 + z * ³√4 = 0 (Posted on 2009-10-15)

Each of x, y and z is a rational number such that: x + y * ³√2 + z * ³√4 = 0.

Prove that x=y=z=0 is the only possible solution to the above equation.

See The Solution Submitted by K Sengupta

Rating: 3.0000 (1 votes)

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re(4): Solution - Extra font facility

| Comment 7 of 14 |

(In reply to re(3): Solution - Extra font facility by Charlie)

So even that doesn't work.

Posted by Charlie on 2009-10-15 22:44:44

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