A chunk of pages is missing from a book. The sum of the missing page numbers is 9808. What are those page numbers?
For an even sum the pages must be multiples of 4 and in the order of odd-even.
The sum of pages is given by the triangular sequence N*(N+1)/2 while the sequence of sums of multiples of 4 is given by 8N^2+2N.
At any point "y" the sum may be expressed by a triangular number plus a constant [K] and the sum at the next term "y+1" will be the next triangular number plus K.
Using those principles in a spreadsheet and by reiteration I subtracted successive 4N multiples from 9808 and then divided by 4N. If the quotient was an integer then I would have K. The missing pages would therefore be from K+1 to K+4N.
4N N 8N^2+2N K
4 1 10 9808 9798 2449.5
8 2 36 9808 9772 1221.5
12 3 78 9808 9730 810.8333
16 4 136 9808 9672 604.5
20 5 210 9808 9598 479.9
24 6 300 9808 9508 396.1667
28 7 406 9808 9402 335.7857
32 8 528 9808 9280
290 36 9 666 9808 9142 253.9444
The integer K occurs for 4N=32 so the pages are from 291 to 322.
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Posted by brianjn
on 2009-11-13 21:37:44 |