Consider the following two sets:
Set A = { 2,3,4,6 }
Set B = { 2,5,7,9 }
What is the probability that two randomly chosen elements from B would add up to be more than the product of two randomly chosen elements from A?
15 of 36, after manually working out all the cases using a simple "yes and no" method. There are 15 cases where the sum of B is Greater to the Product of A, and 19 cases where the Product of A is greater than the sum of B, this leaves 2 cases, ehich are those where the equal the same ( 2 cases in A = 12, 1 case in B = 12) 15/36 is the correct answer
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Posted by Tristan
on 2003-04-26 11:51:46 |