The function G is such that each of G, G’ and G” exists and is continuous on the interval [0, e].

It is further known that G’(e) = G(e) = G’(1) = G(1) = 1, and:

e
∫ G’(y)* y^-2 dy = 0.5
1

Evaluate:

e
∫ G”(y)*ln y dy
1

Note: ln y denotes the natural logarithm of y.

(In reply to Time for a solution, KS? by JayDeeKay)

Or at least a hint.  I couldn't make any headway worth sharing.

Posted by Jer on 2010-02-18 13:16:20