The function G is such that each of G, G’ and G” exists and is continuous on the interval [0, e].

It is further known that G’(e) = G(e) = G’(1) = G(1) = 1, and:

e
∫ G’(y)* y^-2 dy = 0.5
1

Evaluate:

e
∫ G”(y)*ln y dy
1

Note: ln y denotes the natural logarithm of y.

V-e-r-y suspicious, Harry!

Still awaiting the analytical solution.    :-)

Posted by JayDeeKay on 2010-02-21 21:17:55