Determine all possible pair(s) (x, y) of positive integers that satisfy the equation:
x3 = y2 – 15
(In reply to
re: Fascinating by ed bottemiller)
The way I saw the equation was x^3-1 = (y+4)(y-4); the differences between successive terms on the RHS are just the odd numbers, so one might instinctively (but obviously quite wrongly!) think that there should be an infinity of solutions - e.g. 1259712^2-15 = 11664^3; but as you mentioned earlier, there always seems to be a problem in the sixth place of decimals. But I would like to see some proof that there are in fact no such solutions, before writing this one off!
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Posted by broll
on 2010-07-09 14:20:51 |
re(2): Fascinating
