perplexus.info :: Just Math : 18-yes, 17-maybe

18-yes, 17-maybe (Posted on 2010-08-06)

Prove that among any 18 consecutive 3-digit numbers there must be at least one which is divisible by the sum of its digits.

No Solution Yet Submitted by Ady TZIDON

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re: a beautiful computer proof

| Comment 2 of 4 |

(In reply to computer proof by Charlie)

Beautiful indeed!

Not only you have proven the 18-yes but upgraded
the 17-may-be to 17-no by listing all existing
17 numbers strings.

Now- not a big deal- try to solve it analytically.

Ady

Posted by Ady TZIDON on 2010-08-06 16:20:21

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