1. 3^M+4^M is odd, so even M merit no further consideration.
2. By reason of addition/multiplication of powers, we need further only check odd prime M.
3. If M is odd prime, then we have 3^(M-1) congruent to 1 and 4^(M-1) congruent to 1, modM (Fermat).
4. Hence, 3^M is worth 3, mod5 or larger and 4^M is worth 4, mod5 or larger.
5. Accordingly, M is always divisible by 7.
Edited on November 13, 2010, 12:40 pm
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Posted by broll
on 2010-11-13 12:39:18 |