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Sum (expression) = 10*n (Posted on 2011-02-22) Difficulty: 3 of 5
Determine all possible positive integer values of n that satisfy this equation:
Σj=n

j=1
(x+j-1) (x+j) = 10*n

whenever x is an integer.

Note: For a desired value of n, the above equation holds true for at least one value of x.

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (2 votes)

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Possible solution | Comment 2 of 5 |

According to my (clumsy to non-existent) powers of analysis:

1/3(n^3+3n^2x+3nx^2-n) = 10n
n^3/3+n^2x+nx^2-n/3 = 10n
n^2/3+nx+x^2-1/3=10
n^2+3nx+3x^2-1=30
n^2+3nx+3x^2 = 31

{n,x}={-11,5}{-11,6}{-7,1}{-7,6}{-4,-1}{-4,5}{4,-5}{4,1}{7,-6}{7,-1}{11,-6}{11,-5}

The positive integer values of n are 4,7,11, when x is a (positive or negative) integer.

Edited on February 23, 2011, 7:15 am
  Posted by broll on 2011-02-23 07:08:40

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