Integers equal to each other or differing by 1 will be called "almost equal " within the contents of this problem.

In how many ways can 2011 be expressed as a sum of almost equal addends?
The order of the addends in the expression is immaterial.

(In reply to Now I remember the D1 way. by Jer)

BRAVO!

You have solved it correctly, just  edit your example :  2011= 402+402+402+402+403,
not the way you wrote.

Edited on April 1, 2011, 6:29 pm

Posted by Ady TZIDON on 2011-04-01 18:19:23