Integers equal to each other or differing by 1 will be called "almost equal " within the contents of this problem.

In how many ways can 2011 be expressed as a sum of almost equal addends?
The order of the addends in the expression is immaterial.

Can you really have the sum of one addend?

Shouldn't the answer be 2010 ways of having actual sums?

Posted by Charlie on 2011-04-01 23:22:11