(In reply to
re: Oh wait - I gottit! by Cheradenine)
What Nick is saying (I think) is that if you draw a line through D perpendicular to the base BC and call the intersection F, it will divide the angle BDE (=2a) into two angles: BDF = a/2 and FDE=3a/2.
|
Posted by TomM
on 2002-06-19 02:49:25 |