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An extended harmony (Posted on 2011-11-01)

How many members of the harmonic series 1+1/2+1/3+1/4+ …+1/n are needed to add up close to 10 , without going over it?

No Solution Yet Submitted by Ady TZIDON

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Implementation in Mathematica.

| Comment 4 of 5 |

HarmonicNumber[n] = 10, n=12366.4681065866...

So the closest integer value is 12366.

Posted by broll on 2011-11-02 05:50:02

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