Two trains, A and B, leave their respective starting points at the same time and travel in opposite directions. They travel at constant speeds, and pass at point M. One travels at twice the speed of the other. If one of the trains leaves five minutes late they pass at a point 2 miles from point M.
What is the speed of the slow train, in miles per hour?
The time difference of 5 min causes the two trains meet at 2 miles farther travelling at a relative speed of v+2v=3v
Then 3v=2miles/5mins then v=8 miles per hour
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Posted by Max
on 2003-05-10 09:50:53 |