Find a three-digit number containing three different digits where the following are all perfect squares:
(A) The sum of the first digit and the number formed by the second and third digits;
(B) The first digit multiplied by the number formed by the second and third digits and
(C) The sum of the three digits.
The three-digit number is 916. As a check:
A) 9 + 16 = 25 = 5^2
B) 9 * 16 = 144 = 12^2
C) 9 + 1 + 6 = 16 = 4^2
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Posted by Chris
on 2003-05-15 07:11:00 |
Solution
