Find a three-digit number containing three different digits where the following are all perfect squares:
(A) The sum of the first digit and the number formed by the second and third digits;
(B) The first digit multiplied by the number formed by the second and third digits and
(C) The sum of the three digits.
Another possible solution is 808 because:
a) 8+08= 16
b) 8*08= 64
c) 8+0+8= 16
another solution
