Find a three-digit number containing three different digits where the following are all perfect squares:
(A) The sum of the first digit and the number formed by the second and third digits;
(B) The first digit multiplied by the number formed by the second and third digits and
(C) The sum of the three digits.
(In reply to
re: solution (More confusing!) by Gamer)
I start being lost when you say
a+b+c=y^2, a+10b+c=x^2
and that these lead to
9b = y^2-x^2.
Perhaps a typo in the interchange of x and y in one or the other of the lines, but not knowing which discourages me from reading further.
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Posted by Charlie
on 2003-05-16 08:03:20 |
re(2): solution (More confusing!)
