Find all values of b such that the equation
bx = logbx
has exactly one real solution.
(In reply to
SPOILER by Ady TZIDON)
1^x = 1. log(1) = 0. So I'm not too sure that 1 is a solution, particularly if x = 1 as well.
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Posted by broll
on 2012-12-13 05:54:17 |