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Rocking digits (Posted on 2013-02-08)

Identify the last two digits of the given number:

9^{8^{7^{6^{5^{4^3²}}}}}

No Solution Yet Submitted by Danish Ahmed Khan

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possible answer

| Comment 1 of 3

Let L2D(K) denote the 2 last digit of a number K

CLEARLY L2D(5^ anynumberover1)=25

L2D(6^25)=76 (.... LIKE L2D(6^5)......)

L2D(7^76)=01 (..... LIKE L2D(7^0)....)

L2D(8^1)=8

L2D(9^8)=21

21, the lucky number is the answer, IF I did not err...

Posted by Ady TZIDON on 2013-02-08 16:53:33

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