Given:

    x,y,z > 0
    xy+yz+zx <= 3/4

and

    P=x+y+z+(1/x)+(1/y)+(1/z)

Find the Minimum Value of P. Find x, y, and z when P = Minimum Value.

(In reply to Wrong ! by vohonam)

Wait a minute, you're telling me to use Cauchy's inequality, and you're not even doing fractions properly? My answer was 7 1/2. That's the same as 15/2.

Posted by friedlinguini on 2002-06-20 08:25:25