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Dark Divisibility (Posted on 2013-04-27) Difficulty: 3 of 5
The natural numbers a,b,c,d are such that their least common multiple equals a+b+c+d. Prove that abcd is divisible by 3 or by 5.

No Solution Yet Submitted by Danish Ahmed Khan    
Rating: 3.7500 (4 votes)

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Some Thoughts one example | Comment 3 of 21 |

(1,2,2,5)  fits, did not look for other examples.

If there are none - then this is a proof.

If one lists  ALL   examples that fit - it is ok as well.

I have nothing to add.


  Posted by Ady TZIDON on 2013-04-28 09:24:25
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