All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Minimum Value (Posted on 2002-06-19) Difficulty: 5 of 5
Given:
    x,y,z > 0
    xy+yz+zx <= 3/4
and
    P=x+y+z+(1/x)+(1/y)+(1/z)
Find the Minimum Value of P. Find x, y, and z when P = Minimum Value.

See The Solution Submitted by vohonam    
Rating: 3.2500 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Hey ! | Comment 6 of 18 |
I just posted all my solution to this comment.What's wrong ?. This commemt just displayed wrong solution. Why. May be I post to Levik. That is why this web, I can't post picture. Suck !
  Posted by vohonam on 2002-06-20 16:08:10
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information