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Reciprocal Equation #4 (Posted on 2013-07-20) Difficulty: 3 of 5
Find all triplets (A, B, C) of nonzero integers with A ≤ B ≤ C satisfying:

(1 + 1/A) (1 + 1/B) (1 + 1/C) = 3.

Prove that there are no others.

Note: There may be more than one solution.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: answer - spoiler | Comment 2 of 3 |
(In reply to answer - spoiler by Ady TZIDON)

 There may be at least one more solution involving negative  and positive integers.

  Posted by K Sengupta on 2013-07-20 11:47:05

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