perplexus.info :: Just Math : Perfectly Harmonic

Perfectly Harmonic (Posted on 2013-11-13)

Each of the three positive integers (81+K), (162+K) and (337+K) is a perfect square such that their positive square-roots are in harmonic sequence.

Determine the value of K, and prove that no other value for K is possible.

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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re(2): Solution

Comment 3 of 3 |

(In reply to re: Solution by Math Man)

If n=0, then K=-81, so K+81=0 is a square

0 is not a positive integer.

Posted by Ady TZIDON on 2013-11-15 02:57:11

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